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Omphaloskeptic
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Join Date: Apr 2013
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Old March 23rd, 2015, 08:54 AM
Why doesn't the Permanent flaw, when added to a sustained effect (Growth, for example), lower the cost by -1/level? I can't find any reason it shouldn't in the rules -- am I missing something?

And speaking of Growth, are there plans to fix the 'Limited to Increasing Size Only' flaw?
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Omphaloskeptic
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Old March 23rd, 2015, 10:08 AM
Alright: sorry. Went and confused myself. The core rulebook does specifically say that the Permanent flaw, when applied to Growth, is a "+0 cost per rank" flaw.

What I should have asked is: why does the Permanent Flaw work the same way for other sustained-duration effects (Concealment is a good example) when it claims to be "-1 cost per rank" when listed elsewhere?
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charlieluce
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Old March 23rd, 2015, 07:15 PM
As per the description of Permanent, "A continuous effect with this flaw becomes permanent in duration."

So an effect that starts out as Sustained has to have the Increased Duration Extra applied to it (as +1 cost per rank) to make it Continuous before the Permanent Flaw can be applied to it (at -1 cost per rank, for a net +0).

This could really be explained better in the book, but it is consistent.

Currently Running: Pathfinder Second Edition
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Former HL Games: D&D 4e & 5e, Mutants & Masterminds 2E & 3E, Savage Worlds
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Omphaloskeptic
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Old March 23rd, 2015, 07:25 PM
Quote:
Originally Posted by charlieluce View Post
As per the description of Permanent, "A continuous effect with this flaw becomes permanent in duration."

So an effect that starts out as Sustained has to have the Increased Duration Extra applied to it (as +1 cost per rank) to make it Continuous before the Permanent Flaw can be applied to it (at -1 cost per rank, for a net +0).

This could really be explained better in the book, but it is consistent.
Ah. That explains it. I tried it on an instant power, too, and the math seemed to work out, but what was actually taking place was not clear.

Thanks, though.
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